If, in first order kinetics, 50 percent of a drug is
absorbed from an intramuscular site in 12 minutes, then 75
percent drug is absorbed in how much time?
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Answer / kassahun woubeshet
Say you are given 100% of a certain drug; for this drug to
go by (1/2)50%, it takes 12 min and the remaining 50% to go
by another 1/2 and become 25%, it takes another 12 min. So
if you add 12 min + 12 min you would get 24 min.
100%
.
....12min (1/2 of the 100% to be absorbed)
.
50%
.
....12min (1/2 of the 50% to be absorbed)
.
25% at this point the drug has been absorbed by 75%
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