Answer / durga bhavani

void main()
{
int a[25],n,i,sum=0;
printf("enter n value");
scanf("%d",&n);
printf("\n Enter the numbers");
for(i=0;i<n;i++)
{
scanf("%d",&a[i]);
}
for(i=0;i<n;i++)
sum+=a[i];
printf("\nSum of the given numbers is %d",sum);
}

Answer / chandra

#include<stdio.h>
#include<conio.h>
main()
{
int a[25],n,i,sum=0;
printf("enter n value");
scanf("%d",&n);
printf("\n Enter the numbers");
for(i=0;i<n;i++)
{
scanf("%d",&a[i]);
}
for(i=0;i<n;i++)
sum+=a[i];
printf("\nSum of the given numbers is %d",sum);
}

Answer / prince rafi

void main()
{
int sum,a=6,b=3;
clrscr();
sum=a+b;
printf("%d",sum);
}
getch();
}

Answer / koushik sarkar

#include<stdio.h>
#include<conio.h>
void main()
{
int a,b;
clrscr();
printf("Enter a integer no:-"); scanf("%d",&a);
printf("Enter a Integer no:-"); scanf("%d",&b);
printf("Sum= %d",a+b);
getch();
}

Answer / arunkumar

#include<stdio.h>
#include<conio.h>

fun(int n);
int main()
{
int n=10;
printf("%d",fun(10));
}
fun(int n)
{
if(n<1)
return n;
else
return (n+fun(n-1));
}

Answer / neha shree

void main()
{
int a,n,i,sum=0;
printf("enter n value");
scanf("%d",&n);
printf("\n Enter the numbers");
for(i=0;i<n;i++)
{
scanf("%d",&a[i]);
}
for(i=0;i<n;i++)
sum+=a[i];
printf("\nSum of the given numbers is %d",sum);
}

Answer / vignesh1988i

here the program uses dynamic memory allocation concept instead of arraya......


#include<stdio.h>
#include<conio.h>
void main()
{
int *pointer,n,sum=0;
clrscr();
printf("enter no. of elements :");
scanf("%d",&n);
pointer=(int*)malloc(n*sizeof(int));
for(int i=0;i<n;i++)
{
scanf("%d",(pointer+i));
sum=sum+(*(pointer+i));
}
printf("the sum is :%d",sum);
getch();
}


thank u

Answer / ruchi

#include<stdio.h>
#include<conio.h>
int main()
{
int n,m,m1,s=0,d,sum;
printf("\nEnter the number ");
scanf("%d",&n);
m=n%10;
d=n/10;
while(d>=10)
{
m1=d%10;
d=d/10;
s =s+m1;
}
sum=s+m+d;
printf("\nSum is %d",sum);
getch();
}

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0 Answers