Answer / thiru

Age 40

Answer / harini

y=x+30 (Father is 30 years older than his son x-Son,y-Father),
After 5 years
y+5=3(x+5)

y-x =30
y-3x =10
----------
2x = 20
-----------
x=10
y=x+30=10+30=40

Answer / bhavani

s = son

f=father

step 1: f=s+30
f-s=30 equation (1)
step 2: f+5 = 3(s+5)
f+5=3s+15
f-3s=10 equation (2)
by (1) & (2) we get s = 10 substituting it in equation (1)
we get f=40. The father's present age is 40

cross check : the present age of father is 40 after 5 years
his age would be 45 which is thrice of his son's present age
(i.e 15)

Answer / esha prasad

Father=Son+30 or Son= Father-30

Father+5 = 3(Son+5)

Father+5 = 3(Father-30+5) /* < as Son= Father-30>*/
Father+5 = 3Father-75

Father=3Father-80
0=2Father-80

Father=40

Answer / karthika

let
Present------------son age=x,father age=x+30
after 5 years------son =x+5 ,father =x+30+5

its given after 5 yrs,
x+30+5=3(x+5)
x+35=3x=15
3x-x=35-15
2x=20
x=10
father age=x+30
=10+30
=40

Answer / emma

The father is currently 40 and his son is currently 10...
after 5 years 15*3=45 as required :)

Answer / santosh

Father =son and -son * father
father =30
son*3=
father is
90_ 3=60
after five yrs father age must be 45

Answer / bindu

45

Answer / poonam

Father age is older than his son i.e, 30 on that time.

after 5 years father age is thrice of his son age.

Son age multiply in to 3 times.

====>>>> 15*3= 45 years.

Therefore son age is 15 years and the father age is 45
years.

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