In a hotel, rooms are numbered from 101 to 550. A room is
chosen at random. What is the probability that room number
starts with 1, 2 or 3 and ends with 4, 5 or 6?
Answers were Sorted based on User's Feedback
Answer / manpreet singh
Answer is 1/5(0.20)
Favourable rooms= 1z4(where z=0,1,2,3,4,5,6,7,8,9)=10
total favourable rooms=90
|Is This Answer Correct ?||10 Yes||2 No|
Answer / guest
There are total 450 rooms.
Out of which 299 room number starts with either 1, 2 or 3.
(as room number 100 is not there) Now out of those 299
rooms only 90 room numbers end with 4, 5 or 6
So the probability is 90/450 i.e. 1/5 or 0.20
|Is This Answer Correct ?||9 Yes||2 No|
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