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number 2 plssssss help !!....using array.. turbo c..
create a program that will accept a number and determine if
it is a happy number or an unhappy number..
example:
enter a number : 7
7*7=49
then 4 and 9
4*4 and 9*9== 16 + 18 gives you 97
then 9 and 7
9*9 and 7*7 == 81 + 49 gives you 130
then 1 and 3
1*1 and 3*3 == 1 + 9 gives you 10
1*1 gives you 1
sample output:
7= 49= 16+81= 97= 81+49=130 =1+9=10 =1
"7 is a happy number"
. if the last number is 2 then the number being inputed is
not a happy number.
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Answer / swapnil chhajer
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
int happyNumber(int n)
{
char temp[10];
itoa(n,temp,10);
int len=strlen(temp);
int ret,sum=0,i;
if(n==1)
return 1;
else if(n==4)
return 0;
else
{
for(i=0;i<len;i++)
sum += (temp[i]-48)*(temp[i]-48);
ret = happyNumber(sum);
}
return ret;
}
int main()
{
int n;
printf("Enter the number : ");
scanf("%d",&n);
if(happyNumber(n) == 1)
printf("\n\n%d is a HAPPY NUMBER",n);
else
printf("\n\n%d is NOT A HAPPY NUMBER",n);
fflush(stdin);
getchar();
return 0;
}
| Is This Answer Correct ? | 6 Yes | 3 No |
Answer / y hussain reddy
void main()
{
int n;
int f(int);
printf("nter number");
scanf("%d",&n);
while(n>9)
{
n=f(n*n);
}
if(n==1)
printf("%d is happy number",n);
else
printf("%d is unhappy number",n);
}
int f(int n)
{
int s=0;
while(n)
{
s+=(int)pow(n%10);
n=n/10;
}
return s;
}
| Is This Answer Correct ? | 5 Yes | 4 No |
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