Answer / sneh nagaonkar

/*Program to takes the the data of a 3x3 matrix and check if the given matrix is magic

square or not*/
#include <stdio.h>
#include <conio.h>
int num[3][3];
int sum[8];
int r,c,i;

/*Function to take the value in matrix from user*/
void read_matrix()
{
for(r=0;r<3; r++)
{
for(c=0;c<3; c++)
{
printf("Enter value for %d %d::",r,c);
scanf("%d",&num[r][c]);
}
}
}

/*Function to print matrix and get the sum of rows,cols and diaglons*/
void print_calc_rows_cols()
{
int sum_row,sum_col,ctr=0;

/*Print the Matrix and get the sum of rows*/
for(r=0;r<3; r++)
{
sum_row=0;
for(c=0;c<3; c++)
{
printf("\t%d",num[r][c]);
sum_row=sum_row+num[r][c];
}
sum[ctr]=sum_row;
ctr++;
printf(":: %d",sum_row);
printf("\n");
}
printf("\t::\t::\t::\n");

/*Get the sum of columns*/
for(c=0;c<3;c++)
{
sum_col=0;
for(r=0;r<3;r++)
sum_col=sum_col+num[r][c];

sum[ctr]=sum_col;
ctr++;
printf("\t%d",sum_col);
}
printf("\n");

/*Get the sum of diagnols*/
sum[6]=num[0][0]+num[1][1]+num[2][2];
sum[7]=num[0][2]+num[1][1]+num[2][0];

}

/*Function to Check the sum of rows,cols and diagnols*/
char check_matrix()
{
char c;
for(i=0;i<3; i++)
{
if(sum[i]==sum[i+1])
c='y';
else
{
c='n';
break;
}
}
return c;
}

void main()
{
char c;
clrscr();
read_matrix();
print_calc_rows_cols();
c=check_matrix();


/*Print the result*/
if(c=='y')
printf("\nThis Matrix is a Magic Square");
else
printf("\nThis Matrix is Not a Magic Square");

getch();
}

Performance Algorithm A performs 10n2 basic operations and algorithm B performs 300 lg n basic operations. For what value of n does algorithm B start to show its better performance?

0 Answers   ASD Lab, Qatar University, UNV,

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