Answer / biju

answer is correct upto x^2-x-2=0
then (x-2)(x+1)=0
then x=2 or x=-1
only admissible value is x=2

Answer / heyyrashmi

let Sqrt(2+Sqrt(2+Sqrt(2+.....=x;
So, x=Sqrt(2+x);
Squaring both side
we get, X^2=x+2
or, x^2-x-2=0
or, x^2-2x+x-2=0
or,x(x-2)+1(x-2)=0
or,(x-2)(x+1)=0
Hence, x=2 or x=-1(Since x cant be negative. )
So x=2 Ans.

Answer / pramod r prakash

Let x be equal to the given expression Squareroot(2+Sqrt
(2+Sqrt(2.............
x=sqrt(2+x)
squaring both sides we get
xsquare=2+x
or
xsquare-x-2=0
which is nothing but a quadratic equation
after solving this you ll get x to be 1 or -2[rejected
because sqrt of some no. cant be negative]
so the answer is 1

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