Answer / vaibhav srivastava

#include<stdio.h>

int main()
{
char str[50];
int i,j,k;
printf("\nEnter the string\t");
fflush(stdin);
gets(str);
puts(str);

for (i=0; str[i]!='\0';i++);
for ( k=i; k>0; k--)
{ if ( str[k]==' ' || k==i)
{ for( j=k-1; (str[j]!=' ') && (j!=-1) ;j--);
{
while ( ++j!=k)
{printf("%c", str[j]);}
printf(" ");


}


}


}

printf("\n");

}

Answer / charan

#include <stdio.h>
#include <conio.h>
void main()
{
char *str;
char s[10][10];
int i=0,j=0,p=0;
clrscr();
printf("Enter the string");
gets(str);
while(str)
{
if(str[i]!=' ')
s[j][p++]=str[i];
else
{
s[j][p++]='\0';
p=0;
}
i++;
}
for(i=j;i>=0;i--)
puts(s[i]);
getch();
}

plssssss help !!....using array.. turbo c.. create a program that will accept number of words to be consored. .a word must not exceed 10 characters long .the text to be entered will be no longer than 200 characters .there will be no 10 words example: enter number of words to be censor: 5 enter words to censor: windows office microsoft bill gates enter text to censor: bill gates founded microsoft and makes office and windows sample output: <consored> <censored> founded <censored> and makes <censored> and <censored>

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