Answer / abdur rab

#include <stdio.h>

void permute ( char* strptr, int start, int length )
{
int count1;
int count2;
int temp;

for ( count1 = start; count1 < length - 1;
++count1 ) {
for ( count2 = count1 + 1; count2 < length;
++count2 ) {
temp = strptr [ count1 ]; strptr [
count1 ] = strptr [ count2 ]; strptr [ count2 ] = temp;
permute ( strptr, count1 + 1,
length );
temp = strptr [ count1 ]; strptr [
count1 ] = strptr [ count2 ]; strptr [ count2 ] = temp;
}
}
printf ( "\n%s", strptr );
}

int main ( int argc, char* argv [] )
{
char str[] = "abcd";

permute ( str, 0, ( strlen ( str ) ) );

return 0;
}

Answer / ashok kannan

#include<stdio.h>
#include<conio.h>
#include<string.h>

char a[10];
int m;

void permute(int n,int i)
{
int j;
for(j=i;j<m;j++)
{
printf("%c",a[j]);

if(n!=0)
{
permute(n-1,i+1);
}
else
{
printf("%c\n",a[j]);
}

}

void main()
{
printf("enter the string to be permuted");
scanf("%s",a);
m=strlen(a);
permute(m,0);
}

The program will first compute the tax you owe based on your income. User is prompted to enter income. Program will compute the total amount of tax owed based on the following: Income Tax 0 - $45,000 = 0.15 x income $45,001 - $90,000 = 6750 + 0.20 x (income – 45000) $90,001 - $140,000 = 15750 + 0.26 x (income – 90000) $140,001 - $200,000 = 28750 + 0.29 x (income – 140000) Greater than $200,000 = 46150 + 0.33 x (income – 200000) Dollar amounts should be in dollars and cents (float point numbers with two decimals shown). Tax is displayed on the screen.

0 Answers   Microsoft,

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#include <stdio.h> int main ( int argc, char* argv [ ] ) { int value1 = 10; int value2 = 5; printf ( "\n The sum is :%d", value1 | value2 ); } This is the answer asked by some one to add two numbers with out using arithmetic operator?Yes this answer is write it given out put as 15.But how????? what is need of following line? int main ( int argc, char* argv [ ] ) how it work?what is the meaning for this line? please explain me.Advance thanks

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