Answer / e v n raja

#include<stdio.h>
#include<conio.h>

void main()
{
int a[5],i,ele;


clrscr();

printf("enter the array elements
");

for (i=0; i<5; i++)
scanf("%d",&a[i]);

printf("Enter the element to be search
");
scanf("%d",&ele);

// searching for the element

for (i=0; i<5; i++)
{
if (a[i]==ele)
{
printf("Element found %d , position==%d",ele,i);
break;
}
}

} // end of main()

Answer / laxmi

#include<stdio.h>
#include<conio.h>
void main()
{
int a[5]={1,2,3,4,5};
int i;
clrscr();
printf("
enter the value");
scanf("%d",&i);
for(i=0;i<5;i++)
if(i<5)
{
printf("
the value is present=%d");
}
else
{
printf("
the value is absent=%d");
}
getch();
}

Answer / vs

#include<stdio.h>
#include<conio.h>
void main()
int a[5],i;
int e,t=0,p=0;
clrscr();
printf("enter the array of elements/n");
for(i=0;i<5;i++)
scanf("%d",&a[i]);
clrscr();
printf("enter the element to search/n");
scanf("%d",&e);
for(i=0;i<5;i++)
{
if(a[i]==e)
{
t=1;
p=i;
}
}
if(t==1)
printf("element found--%d/n position--%d",e,p);
else
printf("element not found/n");
getch();
}

Answer / satys

we can use any variable in the place of temp

Answer / aishwarya rajan

#include<iostream.h>
#include<conio.h>
void main()
{
int i,n,a[30];
char item;
cout<<"Enter the number of elements you would like to enter in the array: ";
cin>>n;
for(i=0;i<n;i++)
{
cout<<"Enter the element"<<i+1<<" :";
cin>>a[i];
}
cout<<"Enter the element you are searching for in the array:";
cin>>item;
if(a[i]==item)
cout<<"The item does exist in the array!! it is the "<<i+1<<" element!!";
else
cout<<"The item is not found in the array!!";
getch();
}

Answer / priya chauhan

Find the presence of a given number in a set of numbers
using array. also find the position of the number.

Answer / jamshed

IF WE STORE ELEMENTS IN AN ARRAY :


import java.io.*;
class Search
{
public static void main()throws IOException
{
InputStreamReader isr=new
InputStreamReader(System.in);
BufferedReader br=new BufferedReader(isr);
int a[]={5,7,9,11,15,20,30,45,89,97};
int i,n,c=0;
System.out.println("Enter a Number to Search");
n=Integer.parseInt(br.readLine());

for(i=0;i<a.length;i++)
{
if(a[i]==n)
{
c++;
System.out.println("\nThe Number "+n+"
Does Exist");
System.out.println("The Position is
"+(i+1));
}
}
if(c==0)
System.out.println("Search Element Not Found");
}
}

Answer / all

#include<stdio.h>

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