Answer / tase

a more generic implementation + error checking
(observation: if we have 100 100 99 then the 2nd largest is
considered 100 and not 99)



#include <stdlib.h>
#include <stdio.h>
#include <iostream.h>

#define NR_INPUTS 20


void print_nth_larger(int nth_larger, int *int_array)
{
int ordered_nth[NR_INPUTS];
if(nth_larger > NR_INPUTS || nth_larger < 1)
{
cout << "Illegal nth parameter, valid values are from 1 to
" << NR_INPUTS << endl;
return;
}
ordered_nth[0]=int_array[0];
for(int i=1; i < NR_INPUTS; i++)
{
for(int j = 0; j < nth_larger; j++)
{
if(int_array[i] > ordered_nth[j])//if current value from
array is greater than current from ordered
{
for(int k = nth_larger-1; k > j ; k--)
ordered_nth[k]=ordered_nth[k-1];//shifting all other
smaller values to the right by 1
//now inserting the current input number in the ordered
array of the first nth elements
ordered_nth[j] = int_array[i];
break;//getting out of this for loop as we already
inserted the value in the ordered array

}
}
}//end for for the 20 elements array
//now let's print the nth
cout << "The " << nth_larger << " larger element of the
array is: " << ordered_nth[nth_larger-1] << endl;
}


int main()
{
//we have to read 20 numbers in an array and print the
second largest
int input_numbers[NR_INPUTS]; //Allocating memory for input
data

cout << "Please input each number one by one then press
[enter]" <<endl;

char *input_data = new char[100]; //here we should either
use more or do it dynamically


for(int i=0;i < NR_INPUTS;i++)
{
bool invalid_number = true;
while(invalid_number)
{
cin >> input_data;

input_numbers[i] = atoi(input_data);
if(input_numbers[i] != 0 || strcmp(input_data, "0") ==
0)//to be able to input 0 also
invalid_number = false;
else
{
cout << "You did not put in a number, please try
again!, the input value was" << input_data << endl;
invalid_number = true;
}
}//end while
}//end for
cout << "The input numbers are: " << endl;
for(int i=0; i < NR_INPUTS; i++)
{
cout << input_numbers[i] << ", ";
}
print_nth_larger(2, input_numbers);
}

Answer / mms zubeir

void main()
{
int numbers[20];
int biggest=0, secondBiggest=0;

for(int index = 0; index < 20; ++index)
{
int input;
cin>>input;

if(input == biggest)
continue;

if(input > biggest)
{
secondBiggest = biggest;
biggest = input;
}
else if(input > secondBiggest)
secondBiggest = input;
}

cout<<endl<<"Biggest : "<<biggest<<endl<<"Second
biggest : "<<secondBiggest<<endl;

getch();
}

Answer / sujeet pardeshi

int k;
for(i=0;i<2;i++)
{
max=0;
for(j=n;j>=i;j--)
{
if(a[j]>max)
{
max=a[j];
k=j;
}
}
swap(a[i],a[k]);
}
printf("2nd highest no is:%d",max);

Answer / fahad

#include<iostream.h>
void main()
{
int a[20];
int i;
for(i=o ; i<20 ;i++)
cin>>a[i];
}
int(max=a[0];
for(i=1; i<20; i++)
{
if(a[i]>max) max=a[i];
}
cout<<"\n maimun number is ="<< max<<"\n";
}

Answer / ajit

#include<stdio.h>
void main()
{
int a[20],i,j,temp;
printf("enter the 20 values\n");
for(i=0;i<20;i++)
scanf("%d",&a[i]);
for(i=0;i<20;i++)
{
for(j=i+1;j<20;j++)
{
if(a[i]>a[j])
{
temp=a[i];
a[i]=a[j];
a[j]=temp;
}
}
}
printf("the second largest number is %d\n",a[18]);
}

Answer / ada

oid SecondMax(int *a)
{
int *p = a;
int i, max, smax;

smax = max = *p++;
for(i=1;i<20;i++,p++)
{
if(*p>max)
{
smax = max;
max = *p;
}
}

if(smax!=max)
{
cout<<"The second largest number is "<<smax<<endl;
}
else
{
cout<<"There's no second largest number: all elements are
equal"<<endl;
}
}

Answer / sivaraj

ya i above is correct

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