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explain me with a code snippet about the generation and
handling of null point exceptions.
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Answer / g.arun
class Test
{
public static void main(String[] args)
{
try
{
int a[] = null;
System.out.println(a.length);
}
catch (NullPointerException n)
{
System.out.println(n);
}
}
}
U can try this by changing NullPointerException in catch
block as catch(Exception e){ System.out.println(n);}
and Using throw it is
class Test
{
public static void main(String[] args)
{
int a[] = null;
System.out.println(a.length);
NullPointerException n = new NullPointerException();
throw n;
}
}
Using Throws
class Test
{
public static void main(String[] args) throws
Exception
{
int a[] = null;
System.out.println(a.length);
}
}
That's all friends hope this one helps you
| Is This Answer Correct ? | 0 Yes | 0 No |
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