Answer / balibalo

to the writer of #29:

what you propose doesn't work because at line where you have t.wish(), Java tries to find the wish() method in the Object class (since t is of type Object). As it doesn't exist in that class, your program fails to compile.
Simple.

Uday version compiles because there is not type unconsistency, but it still is an anonymous class call, hence not a correct answer to the root question (answer being already given: NO, you cannot create an instance of an interface but you can create references of it).

Answer / ram

hello uday, ur program is not working

Answer / mallesh

hey uday that is not creating intance for Test interface ,
ur implementing the interface using anonymous class
(unknoun class)

public class Test2 {

public static void main(String[] args) {
Test2 t=new Test2();
Runnable r=new Runnable() {
public void run() {
System.out.println("Hi");

}
}; r.run();
System.out.println(r.getClass().getName().toString());
System.out.println(t.getClass().getName().toString());

}
}

Output:Hi
Test2$1
Test2

Answer / naresh jangili

no we can't create an object to interface and also abstract because two classes are un implememnted class for every un implemented classes we can create only reference varable.
but for every implemented classes we can create objects.
eg: interface A{
public void test()
}
class B implementes A
{
public void test()
{
s.o.p("hello");
}
public static void main(String argss[])
{
B b=new B(); (object creation)
A a1=null; (reference variable)

Answer / abhishek pnadey

you cannot create an instance for interface
in the uday answer ..
he has not write semicolon after the new Test();

Answer / arnold schwarzenegger

Yes we can create an instance of Interface but not directly but by using its subclass. Just check the below code


interface check
{
public void method1();
}
abstract public class B implements check
{

public static void main(String[] args)
{
check c = new check()
{
public void method1()
{
System.out.println("interface B m2");
}
};
c.method1();
}
}

Answer / joginder singh

uday,,,dude where have u used or created an instance of
interface test,,,what u are doing is using a anonymous
inner class and den calling the method using instance of
that class....
dat wasnt d ques...

Answer / akthar

No,we can't create an object to an interface...as told uday he create a anonymous class same as Test interface ..if we remove the interface and method it is working ....so t doesnot act as object to an interface it acts as an anonymous class object...so it invoking its anonymous method..

class Main
{
public static void main(String[] args)
{
Test t=new Test()
{
public void wish()
{
System.out.println("output: hello how r u");
}
};
t.wish();
}
}

Answer / yousif mustafa

I think UDAY is right and he gave the right answer.
We actually couldn't instantiate the interface but we could
instantiate object from class implements this interface and
override all of its methods due to interfaces could only
have abstract methods, but also we can use anonymous inner
class to do that and must override all the abstract method
within creating the object. for ex:

interface Test {
void printA();
void printB();
}

class Inter implements Test {
@Override
void printA() {System.out.println("A from implement");}
void printB() {System.out.println("B from implement");}
}

public class A {
public static void main (String arg[]) {
Test t = new Test() {
void printA() { System.out.println("A form inner"); }
void printB() { System.out.println("B from inner"); }
};
Inter i = new Inter();
t.printA();
i.printA();
t.printB();
i.printB();
}
}

Answer / saroj singh

we can create instance of Interface like..


interface Imployee
{
void Pay();
void Salary();
}

class SeniorSoftEngg : Imployee
{
public void Pay()
{
Console.WriteLine("Inside Pay");
}
public void Salary()
{
Console.WriteLine("Inside Pay");
}
}
class Program
{
static void Main(string[] args)
{
Imployee Emp = new SeniorSoftEngg();
Emp.Pay();
Emp.Salary();

}

}

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