Answer / bal

Method overriding is run time poly

Answer / haridini

At run time it is decided that which version of the same
method should be used. Its basically concept of over
riding.And a very powerful mechanism which is implemented
in java.

Answer / vijayakumar chinnasamy

Method overrrideing is the runtime polymorphism.The
class's "object" only determine which method to called .
eg:
class SuperClassTest
{
public void display(){
System.out.println("Super class");
}
}
class SubClassTest extends SuperClassTest
{
public void display(){
System.out.println("Sub class");
}
}
public class TestPro {



public static void main(String[] args) {

SuperClassTest sub=new SubClassTest();
System.out.print("I am Calling
subclasstest's display() method: ");
sub.display();

SuperClassTest sup=new SuperClassTest();
System.out.print("I am Calling
superclasstest's display() method: ");
sup.display();
}

}


o/p:

I am Calling subclasstest's display() method: Sub class
Note: object is type of SubClassTest
I am Calling superclasstest's display() method: Super class
Note: object is type of SuperClassTest

Note:
Method overloading is compile time polymorphism.The
class "reference" type determine which method to be called.

Answer / guest

In Runtime polymorphism the JVM will decide which version
of the method supposed to used.

for example
class Animal{
public void speak(){
System.out.println("Animal speak method callinfg");
}
}

public class Dog extends Animal{
public void speak(){
System.out.println("Dog speak method calling");
}

public static void main(String args[]){

Animal a = new Dog();

a.speak();// u r calling now Animal class speck metod.
}
}
here JVM will decide to execute Dog version of speck
method . This is called runtime polimorphism

thanks
prasad thota

Answer / tntrichy

Hi Bal, Virtual Function concept in Java, i.e, assigning
sub-class object in super-class's reference.

Answer / ravikiran

overriding

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