#include<stdio.h>
main()
{
char s1[]="Ramco";
char s2[]="Systems";
s1=s2;
printf("%s",s1);
}
Find the output
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Answer / vignesh1988i
it will be an error as for as i know... since s1 is not a
pointer variable... but however array are implict
pointers.... here we cant assign the base address to
another arry which is capable of holding oly values not
addressses...............
| Is This Answer Correct ? | 4 Yes | 1 No |
Answer / geo
Lvalue error.
if char *s1="Ramco";
char *s2="Systems";
s1=s2; is used
ans: Systems
| Is This Answer Correct ? | 3 Yes | 0 No |
Answer / mahadev shinde
ncompatible types in assignment of `s2' to `s1'
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / ankit garg
it will give an error bcoz here we do not give the header
file for string ( #include<string.h>) ... and we can not
use the string without it....
| Is This Answer Correct ? | 1 Yes | 2 No |
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