#include<stdio.h> main() { char s1[]="Ramco";

Categories >> Software >> Programming Languages >> C
Suggest New Category

#include<stdio.h>
main()
{
char s1[]="Ramco";
char s2[]="Systems";
s1=s2;
printf("%s",s1);
}
Find the output

Question Posted / guest

5 Answers
15808 Views
CitiGroup, I also Faced
E-Mail Answers

Answers were Sorted based on User's Feedback

#include<stdio.h> main() { char s1[]="Ramco"; char s2[]="Sy..

Answer / guest

error

Is This Answer Correct ?

15 Yes

1 No

#include<stdio.h> main() { char s1[]="Ramco"; char s2[]="Sy..

Answer / vignesh1988i

it will be an error as for as i know... since s1 is not a
pointer variable... but however array are implict
pointers.... here we cant assign the base address to
another arry which is capable of holding oly values not
addressses...............

Is This Answer Correct ?

4 Yes

1 No

#include<stdio.h> main() { char s1[]="Ramco"; char s2[]="Sy..

Answer / geo

Lvalue error.

if char *s1="Ramco";
char *s2="Systems";
s1=s2; is used

ans: Systems

Is This Answer Correct ?

3 Yes

0 No

#include<stdio.h> main() { char s1[]="Ramco"; char s2[]="Sy..

Answer / mahadev shinde

ncompatible types in assignment of `s2' to `s1'

Is This Answer Correct ?

2 Yes

0 No

#include<stdio.h> main() { char s1[]="Ramco"; char s2[]="Sy..

Answer / ankit garg

it will give an error bcoz here we do not give the header
file for string ( #include<string.h>) ... and we can not
use the string without it....

Is This Answer Correct ?

1 Yes

2 No

Post New Answer