main()
{char a[10]={1,2,3,4,5,6};int x;
for(x=0;x<4;x++){ b[x]=x+'a';}
printf("%s",b);}
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Answer / vignesh1988i
1 st prob.. this will be an error since b[] have not been
declared.......
if you are nt bothered about the syntax obligations....
then the output will be:
abcd
| Is This Answer Correct ? | 5 Yes | 0 No |
What is wrong with this statement? Myname = 'robin';
what will the following program do? void main() { int i; char a[]="String"; char *p="New Sring"; char *Temp; Temp=a; a=malloc(strlen(p) + 1); strcpy(a,p); //Line no:9// p = malloc(strlen(Temp) + 1); strcpy(p,Temp); printf("(%s, %s)",a,p); free(p); free(a); } //Line no 15// a) Swap contents of p & a and print:(New string, string) b) Generate compilation error in line number 8 c) Generate compilation error in line number 5 d) Generate compilation error in line number 7 e) Generate compilation error in line number 1
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