Answer / preethi

y==z true
so, x=1

Answer / guest

y==z checks if both are equal and returns TRUE or FLASE
(1 / 0). In this case y = z = 6, so it returns TRUE / 1. x
= 1.

Answer / amit

since "=" has a low precedence over "==" .. thus "y==z" will
be evaluated first and the returned value will be stored in
x which will be printed subsequently...

In this case since y equals z, x = 1 will be printed

cheers

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Answer / anand n

Ans:1


x=2,y=6,z=6//here x value is:2
x=y==z;//x=6 and y=6 so x is equal to y means its true,now
//x value is 1
printf(%d",x)

Answer / vijoeyz

My apologies for the silly mistake. The value of x is 1 as
everyone has said.

Thanks,
Vijay Zanvar
http://faq.zanvar.in

Answer / priya

answer: 1

Answer / mahadevan

in C language this statement(x=y==z;)is declaration syntax Error

Answer / suchita

here we can not use and conditional statement thats why we can
not say "this is a boolean eq" and thats why x print either 2 or
garbage value

Answer / wasim

First of all the given syntax for printf statement is
wrong.it will not show any output but the syntax error

Answer / manjunath kusagur

in memory first location hold value of x as 2....ofter
assigning x=y..x(6)<-y..value of x is overwritten because
memory location holds only one value at a time means now x
holds value as 6......

Is the below things valid & where it will be stored in memory layout ? static const volatile int i; register struct { } ; static register;

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