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x=2,y=6,z=6
x=y==z;
printf(%d",x)
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Answer / guest
y==z checks if both are equal and returns TRUE or FLASE
(1 / 0). In this case y = z = 6, so it returns TRUE / 1. x
= 1.
| Is This Answer Correct ? | 27 Yes | 0 No |
Answer / amit
since "=" has a low precedence over "==" .. thus "y==z" will
be evaluated first and the returned value will be stored in
x which will be printed subsequently...
In this case since y equals z, x = 1 will be printed
cheers
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| Is This Answer Correct ? | 15 Yes | 0 No |
Answer / anand n
Ans:1
x=2,y=6,z=6//here x value is:2
x=y==z;//x=6 and y=6 so x is equal to y means its true,now
//x value is 1
printf(%d",x)
| Is This Answer Correct ? | 8 Yes | 1 No |
Answer / vijoeyz
My apologies for the silly mistake. The value of x is 1 as
everyone has said.
Thanks,
Vijay Zanvar
http://faq.zanvar.in
| Is This Answer Correct ? | 7 Yes | 2 No |
Answer / mahadevan
in C language this statement(x=y==z;)is declaration syntax Error
| Is This Answer Correct ? | 5 Yes | 2 No |
Answer / suchita
here we can not use and conditional statement thats why we can
not say "this is a boolean eq" and thats why x print either 2 or
garbage value
| Is This Answer Correct ? | 7 Yes | 5 No |
Answer / wasim
First of all the given syntax for printf statement is
wrong.it will not show any output but the syntax error
| Is This Answer Correct ? | 1 Yes | 1 No |
in memory first location hold value of x as 2....ofter
assigning x=y..x(6)<-y..value of x is overwritten because
memory location holds only one value at a time means now x
holds value as 6......
| Is This Answer Correct ? | 0 Yes | 1 No |
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