f()
{
int a=2;
f1(a++);
}
f1(int c)
{
printf("%d", c);
}
c=?
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Answer / jack
in line 4, a's value is pushed on to stack and then
increaments.........In line 6 the function f1 pops the a's
value and assigned to c so .......c is value is 2.......
| Is This Answer Correct ? | 7 Yes | 2 No |
Answer / viji
a++ is postfix operator so it first assigns its values and
then incremented. In above statement the value of a is first
assigned to c and then increment. so the output of c is 2;
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / banavathvishnu
a value will be first assigned to C in the Function and
latter it will be incremented in f() function.
so the value C remains 2
| Is This Answer Correct ? | 0 Yes | 0 No |
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