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input may any number except 1,output will always 1..
conditions only one variable should be declare,don't use
operators,expressions,array,structure
- 4 Answers
- 6283 Views
- IBM, I also Faced
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Answers were Sorted based on User's Feedback
Answer / kesavalu
#include<stdio.h>
#include<conio.h>
main()
{
int d;
printf("enter any no except 1");
scanf("%d",&d);
clrscr();
printf("1");
getch();
}
| Is This Answer Correct ? | 9 Yes | 2 No |
Answer / nila
#include<stdio.h>
#include<conio.h>
main()
{
int a;
printf("Enter the number:");
scanf("%d",&a);
printf("1");
getch();
}
| Is This Answer Correct ? | 3 Yes | 1 No |
#include<stdio.h>
main()
{int a;
printf("%d",scanf("%d",&a));
}
| Is This Answer Correct ? | 9 Yes | 8 No |
Answer / dana
#include<stdio.h>
#include<conio.h>
main()
{
int x;
printf{"enter the num ",x);
scanf("%d",&x);
if(x!=1)
printf("1");
else
printf(" ");
}
| Is This Answer Correct ? | 0 Yes | 0 No |
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