What's wrong with "char *p; *p = malloc(10);"?

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What's wrong with "char *p; *p = malloc(10);"?..

Answer / shruti

the syntax of malloc is wrong.

in your example it should be written as:

char *p;

p = (char *)malloc(sizeof(char));

Is This Answer Correct ?

21 Yes

1 No

What's wrong with "char *p; *p = malloc(10);"?..

Answer / guest

The pointer you declared is p, not *p.

Is This Answer Correct ?

10 Yes

0 No

What's wrong with "char *p; *p = malloc(10);"?..

Answer / parasher

char *p;

p = (char *)malloc(sizeof(char));

Is This Answer Correct ?

8 Yes

2 No

What's wrong with "char *p; *p = malloc(10);"?..

Answer / raj

here syntox of malloc is not fallowed

Is This Answer Correct ?

3 Yes

1 No

What's wrong with "char *p; *p = malloc(10);"?..

Answer / clay

Here,

After char *p;
since pointer p is not initialized it is pointing at some
unknown location.

In the next step, the address of the memory allocated by
malloc() is stored at some garbage location pointed by p.

Here p is never initialized or never assigned any value.

Is This Answer Correct ?

0 Yes

3 No

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