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main()
{
int i=1;
while (i<=5)
{
printf("%d",i);
if (i>2)
goto here;
i++;
}
}
fun()
{
here:
printf("PP");
}
- 3 Answers
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Answer / surenda pal singh chouhan
Compiler error: Undefined label 'here' in function main
Explanation:
Labels have functions scope, in other words The scope of
the labels is limited to functions . The label 'here' is
available in function fun() Hence it is not visible in
function main.
| Is This Answer Correct ? | 16 Yes | 0 No |
Answer / jaroosh
Exactly, to be able to move control flow to here, you would
have to make a long jump using not very common functions
(that do actually more than goto) : setjmp and longjmp
(please look up those functions in google or some C standard
library reference).
| Is This Answer Correct ? | 5 Yes | 1 No |
The program is error because of the "goto" statement can't
jump from one segment to another segment i.e not support for
long jump.
| Is This Answer Correct ? | 3 Yes | 0 No |
What is the output of the program given below #include<stdio.h> main() { char i=0; for(;i>=0;i++) ; printf("%d\n",i); }
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C 
