Predict the output or error(s) for the following:
25. main()
{
printf("%p",main);
}
Answers were Sorted based on User's Feedback
Answer / surenda pal singh chouhan
Some address will be printed.
Explanation:
Function names are just addresses (just like
array names are addresses).
main() is also a function. So the address of function main
will be printed. %p in printf specifies that the argument
is an address. They are printed as hexadecimal numbers.
26. main()
| Is This Answer Correct ? | 28 Yes | 2 No |
Answer / khushboo
i tried it out.. on my system it gives the answer 0291. does
anybodyy esle gets the same answer?
| Is This Answer Correct ? | 12 Yes | 2 No |
what is the c source code for the below output? 10 10 10 10 10 10 10 10 10 10 9 9 7 6 6 6 6 6 6 9 7 5 9 7 3 2 2 5 9 7 3 1 5 9 7 3 5 9 7 4 4 4 4 5 9 7 8 8 8 8 8 8 8 8 9
what is the output for this question: main() { int i=1; printf("%d%d%d",i,i++,++i); }
You have given 2 array. You need to find whether they will create the same BST or not. For example: Array1:10 5 20 15 30 Array2:10 20 15 30 5 Result: True Array1:10 5 20 15 30 Array2:10 15 20 30 5 Result: False One Approach is Pretty Clear by creating BST O(nlogn) then checking two tree for identical O(N) overall O(nlogn) ..we need there exist O(N) Time & O(1) Space also without extra space .Algorithm ?? DevoCoder guest Posted 3 months ago # #define true 1 #define false 0 int check(int a1[],int a2[],int n1,int n2) { int i; //n1 size of array a1[] and n2 size of a2[] if(n1!=n2) return false; //n1 and n2 must be same for(i=0;i<n1-1;i++) { if( !( (a1[i]>a1[i+1]) && (a2[i]>a2[i+1]) ) ) return false; } return true;//assumed that each array doesn't contain duplicate elements in themshelves }
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