Answer / Dayaram Pal

A lazy variable (lazy property) in Swift is a property whose initial value is not computed until the first time it is accessed. This can be useful for reducing the overhead of initializing an object that might not be used, especially when dealing with expensive or time-consuming initialization.

What is memory leak in swift?

1 Answers  

---

What is optional chaining?

1 Answers  

---

What is mvc architecture in swift?

1 Answers  

---

What is dynamic dispatch swift?

1 Answers  

---

What is protocol in swift?

1 Answers  

---

What is instance variable in swift?

1 Answers  

---

Is swift hard to learn?

1 Answers  

---

What are the advantages of using swift?

1 Answers  

---

Is multiple inheritance possible in swift?

1 Answers  

---

Is swift memory safe?

1 Answers  

---

How to convert nsarray to nsmutablearray in swift?

1 Answers  

---

Swift defines the AnyObject type alias to represent instances of any reference type, and it’s internally defined as a protocol. Consider the following code: var array = [AnyObject]() struct Test {} array.append(Test()) This code generates a compilation error, with the following error message: Type 'Test' does not conform to protocol 'AnyObject' The failure is obvious because a struct is a value and not a reference type, and as such it doesn’t implement and cannot be cast to the AnyObject protocol. Now consider the following code: var array = [AnyObject]() array.append(1) array.append(2.0) array.append("3") array.append([4, 5, 6]) array.append([7: "7", 8: "8"]) struct Test {} array.append(Test()) The array array is filled in with values of type respectively int, double, string, array and dictionary. All of them are value types and not reference types, and in all cases no error is reported by the compiler. Why?

1 Answers  

---