Golgappa.net | Golgappa.org | BagIndia.net | BodyIndia.Com | CabIndia.net | CarsBikes.net | CarsBikes.org | CashIndia.net | ConsumerIndia.net | CookingIndia.net | DataIndia.net | DealIndia.net | EmailIndia.net | FirstTablet.com | FirstTourist.com | ForsaleIndia.net | IndiaBody.Com | IndiaCab.net | IndiaCash.net | IndiaModel.net | KidForum.net | OfficeIndia.net | PaysIndia.com | RestaurantIndia.net | RestaurantsIndia.net | SaleForum.net | SellForum.net | SoldIndia.com | StarIndia.net | TomatoCab.com | TomatoCabs.com | TownIndia.com
Interested to Buy Any Domain ? << Click Here >> for more details...


Explain the adapter and memento pattern?


No Answer is Posted For this Question
Be the First to Post Answer

Post New Answer

More Apple iOS Swift Interview Questions

What is dynamic keyword in swift?

0 Answers  


What is tuple in swift?

0 Answers  


What are the advantages of using swift for ios development?

0 Answers  


How can you prioritize the usability of the demand process?

0 Answers  


What are the advantages of swift?

0 Answers  


How to create a tuple in swift?

0 Answers  


What are structures in swift?

0 Answers  


What is use of enum in swift?

0 Answers  


How will you connect ui?

0 Answers  


Swift defines the AnyObject type alias to represent instances of any reference type, and it’s internally defined as a protocol. Consider the following code: var array = [AnyObject]() struct Test {} array.append(Test()) This code generates a compilation error, with the following error message: Type 'Test' does not conform to protocol 'AnyObject' The failure is obvious because a struct is a value and not a reference type, and as such it doesn’t implement and cannot be cast to the AnyObject protocol. Now consider the following code: var array = [AnyObject]() array.append(1) array.append(2.0) array.append("3") array.append([4, 5, 6]) array.append([7: "7", 8: "8"]) struct Test {} array.append(Test()) The array array is filled in with values of type respectively int, double, string, array and dictionary. All of them are value types and not reference types, and in all cases no error is reported by the compiler. Why?

1 Answers  


In swift what is use of backticks while declaring a variable?

0 Answers  


What is difference between weak and strong in swift?

0 Answers  


Categories