Answer / Suneel Kumar Singjh

To find out the K most frequent numbers from a given stream of numbers on the fly, you can use a data structure like a min-heap or a sliding window. Here's an example using a min-heap:nn```pythonnimport heapqnclass FrequentNumberCounter:n def __init__(self, k):n self.k = kn self.counter = {}
self.min_heap = []nn def add(self, num):n if num not in self.counter:n heapq.heappush(self.min_heap, (-num, 0))n self.counter[-num] = 0n self.counter[num] += 1n heapq.heapify(self.min_heap)n self.min_heap = sorted(self.min_heap, key=lambda x:x[0])[:self.k]nn def most_frequent_number(self):n if not self.counter:n return Nonen most_freq, freq = set(), 0n for num, count in self.counter.items():n if count > freq:n freq = countn most_freq.clear()n most_freq.add(num)n elif count == freq:n most_freq.add(num)n return list(most_freq)[0]

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