Answer / chaitanya

In Prolog, in order to process the elements of a list, we have to match them to variables. The method for doing is
We get the head by matching it to a variable
By calling a predicate with the variable, it processes the head
Until you get an empty list repeat the above steps

 What is the output of the following statement? * ( first (rest (first ‘((a b) (c d))))) a) a b) b c) c d) d

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Explain what is the difference between bagof/3 and setof/3 predicate in Prolog?

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 What is the programming structure for LISP?

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Which is used to represent the prompt in lisp? a) # b) $ c) & d) *

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