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What we have to do, when we don't want to implement all
methods of an interface?
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Answer / ravikiran(aptech mumbai)
instead of using interface make use of abstract class at
that moment
| Is This Answer Correct ? | 3 Yes | 1 No |
Answer / aditya mohata
we have to declare that class as an abstract class.
| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / somasundar m
We have to declare that class an abstract class by
declaring that particular unimplemented methods as abstract
method. And you can not create an instance for this class.
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / vinaygeddannavar
YOU SHOULD NOT GO FOR THE INHERIT IN CHILD SPECIFIC CLASS
THATS THE BEST WAY... OTHERWISE IF YOU MAKE IT AS ABSTRACT
CLASS AGAIN YOU NEED TO INHERIT THAT CLASS IN CHILD CLASS OK.
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / mallikarjun
Use another called implementing interface and that class can
be inherited to sub class. This process is called adapter
pattern
| Is This Answer Correct ? | 0 Yes | 0 No |
Is there any way to find whether software installed in the system is registered by just providing the .exe file? I have tried the following code but its just displaying the directory structure in the registry. Here the code : package com.msi.intaller; import java.util.Iterator; import ca.beq.util.win32.registry.RegistryKey; import ca.beq.util.win32.registry.RootKey; public class RegistryFinder { public static void main(String... args) throws Exception { RegistryKey.initialize(RegistryFinder.class.getResource("jRe gistryKey.dll").getFile()); RegistryKey key = new RegistryKey(RootKey.HKLM, "Software\\ODBC"); for (Iterator<RegistryKey> subkeys = key.subkeys(); subkeys.hasNext();) { RegistryKey subkey = subkeys.next(); System.out.println(subkey.getName()); // You need to check here if there's anything which matches "Mozilla FireFox". } } }
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