#include<stdio.h> main() { int a[3]; int *I; a[0]=100;a[1]=

#include<stdio.h>

main()

{

int a[3];

int *I;

a[0]=100;a[1]=200;a[2]=300;

I=a;

Printf(“%d\n”, ++*I);

Printf(“%d\n”, *++I);

Printf(“%d\n”, (*I)--);

Printf(“%d\n”, *I);

}

what is the o/p

a. 101,200,200,199

b. 200,201,201,100

c. 101,200,199,199

d. 200,300

Question Posted / shraddhacpawar

4 Answers
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#include<stdio.h> main() { int a[3]; int *I; a[0]=100;a[1]=200;a[2]=300; I=a..

Answer / shraddhacpawar

Is This Answer Correct ?

17 Yes

2 No

#include<stdio.h> main() { int a[3]; int *I; a[0]=100;a[1]=200;a[2]=300; I=a..

Answer / r.gopala krishnan (gk)

Explanation:
now 'I' variable pointing the base address of the
Array......
1.printf("%d\n",++*I); //I=a[0], bcos I is pointing the
base address. first Increamenting the value so,a[0]=100
become an ( a[0]=101 ).
2.printf("%d"\n,*++I); //This Increment will increment
the address not value. so, now ( I=a[1]=200 ).
3.printf("%d\n",*I--); // now I=a[1]=200 so value will
not change.
4.printf("%d\n",*I); //Now also I=a[1] pointing here only
but a[1]=199, bcos in previous printf after executing we
decrementing the value. a[1]=199......

ANS: a)101,200,200,199

Is This Answer Correct ?

12 Yes

0 No

#include<stdio.h> main() { int a[3]; int *I; a[0]=100;a[1]=200;a[2]=300; I=a..

Answer / kedar

Is This Answer Correct ?

1 Yes

0 No

#include<stdio.h> main() { int a[3]; int *I; a[0]=100;a[1]=200;a[2]=300; I=a..

Answer / ashwini

Is This Answer Correct ?

0 Yes

2 No

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