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what will be the output of this program?
void main()
{
int a[]={5,10,15};
int i=0,num;
num=a[++i] + ++i +(++i);
printf("%d",num);
}
- 6 Answers
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Answer / apekshit jotwani
Answer will be 15.
Consider a[++i]=x
++i=y
++i=z
so v have to evaluate x+y+z
Compiler converts this to postfix as "xy+z+"
so x is put in the stack 1st i=1,x=a[1]=10
Then i=2, 2 is put in the stack
Then x+y is operated = 12
12 is put in the stack.
Then i=3, 3 is put in the stack.
Then 12+3=15,
only 15 is put in the stack. That is the final answer
| Is This Answer Correct ? | 3 Yes | 0 No |
Answer / ricky
Garbage Value
num=a[++i] + ++i +(++i);
in this line the last i will be incremented first
so the last ++i will return 1 after that the middle ++i will return 2 now the value of i will change every where in the program now the first ++i will return 3 since the array starts with a[0] and ends at a[2] there is no a[3] and hence it will print garbage value
| Is This Answer Correct ? | 5 Yes | 3 No |
Answer / abc
initially i=0;
num=a[++i]+ ++i + ++i;
num=a[1]+2+3
num=10+2+3=15
| Is This Answer Correct ? | 1 Yes | 0 No |
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C 
