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import java.io.*;
class Demo
{
public static void main(String args[])
{
File f=new File("1234.msg");
String arr[]=f.list();
System.out.println(arr.length);
}
}
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Answer / sarath
so what is your question..?
the code gives compilation error... because it should throw a IOException..
| Is This Answer Correct ? | 4 Yes | 4 No |
Answer / meziane
The list() of the class java.io.File "returns an array of Strings naming the files and directories in the directory denoted by this abstract pathname."
http://docs.oracle.com/javase/6/docs/api/java/io/File.html#list%28%29
The abstract pathname is the path specified in File f = new File(patAsString).
The method returns null, if the abstract pathname does not denote a directory (i.e an existing directory).
No compilation error.
| Is This Answer Correct ? | 0 Yes | 0 No |
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