import java.io.*; class Demo { public static void main(String args[]) { Fil

import java.io.*;
class Demo
{
public static void main(String args[])
{
File f=new File("1234.msg");
String arr[]=f.list();
System.out.println(arr.length);
}
}

Question Posted / venkiptlr08

3 Answers
6810 Views
IBM, Ramco, I also Faced
E-Mail Answers

Answers were Sorted based on User's Feedback

import java.io.*; class Demo { public static void main(String args[]) { File f=new File("1..

Answer / sri

this code gives Nullpointer exception

Is This Answer Correct ?

6 Yes

0 No

import java.io.*; class Demo { public static void main(String args[]) { File f=new File("1..

Answer / sarath

so what is your question..?
the code gives compilation error... because it should throw a IOException..

Is This Answer Correct ?

4 Yes

4 No

import java.io.*; class Demo { public static void main(String args[]) { File f=new File("1..

Answer / meziane

The list() of the class java.io.File "returns an array of Strings naming the files and directories in the directory denoted by this abstract pathname."

http://docs.oracle.com/javase/6/docs/api/java/io/File.html#list%28%29

The abstract pathname is the path specified in File f = new File(patAsString).
The method returns null, if the abstract pathname does not denote a directory (i.e an existing directory).
No compilation error.

Is This Answer Correct ?

0 Yes

0 No

Post New Answer