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Alok and Bhanu play the following min-max game. Given the
expression N=40+X+Y-Z, where X, Y and Z are variables
representing single digits (0 to 9), Alok would like to
maximize N while Bhanu would like to minimize it. Towards
this end, Alok chooses a single digit number and Bhanu
substitutes this for a variable of her choice (X, Y or Z).
Alok then chooses the next value and Bhanu, the variable to
substitute the value. Finally Alok proposes the value for
the remaining variable. Assuming both play to their optimal
strategies, the value of N at the end of the game would be
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Answer / sowmya
its 49. alok 1st choice 9, bhanu substitutes it to z, 2nd choice 9, she chooses y, 3rd, 9.. she chooses x, then equation wud be 40+9+9-9= 49
| Is This Answer Correct ? | 35 Yes | 10 No |
Answer / joydeep bkp
The answer is 51 ..1st no will b 7 ...vanu wil put it on x..if he puts z=7 then the nxt two numbrs will be 9 9..so ans will be 51 ..now x=7 nxt no will be 5 then if y=5 last no will b zero..so n = 52 ..vanu must put z=5 ..at last alok will give 9..so the result will be 40+7+9-5=51 ...hope its sprite..clear hai? :P
| Is This Answer Correct ? | 8 Yes | 7 No |
Answer / dhamodiran m
N=40
Alok X=8
Bhanu Y-Z= 1-9
Now, N=40+8+1-9
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / sharan
58 ..... alok's first number would be 9 ... bhanu substitutes it for z ... next two numbers of alok would 9 and 9 .. then N=40+9+9-9=58
| Is This Answer Correct ? | 6 Yes | 29 No |
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