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How many four digit numbers can be formed using the digits
1, 2, 3, 4, 5 (but with repetition) that are divisible by 4?
Can you help Alok find the answer?
a) 100 b) 125 c) 75 d) 85
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Answer / sumit kumar
The no divisible by 4 must have last two digit divided by four
so no formed can be
**12
**24
**32
**44
**52
repetation is allowed
so in **12
1st place can be filled in 5 ways
2nd also in 5 ways
there fore 5*5 ways=25
for **12 it is 25 ways
for all=25*5
=125
| Is This Answer Correct ? | 205 Yes | 14 No |
Answer / shatanu kuila
This is a contradictory question.
Bcoz
Any number(minimum three digit number) will be divided by 4, when its last two digit is divided by 4. Here number can be formed through this way **12,**32,**52,**24 but in this problem we can repeat the digit also one formation is **44.
Now we can form those unknown two position 2^5 way (number can be repeated. So for five formation total number will be
=(2^5)5=160. but there is no option.
| Is This Answer Correct ? | 4 Yes | 34 No |
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