4) A number when divided by D leaves a remainder of 8 and
when divided by 3D leaves a remainder of 21 . What is the
remainder left, when twice the number is divided by 3D?
a) 13 b) cannot be determined c) 3 d) 42
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Answer / neelam venkata balaji
let's number is n
so n=Dx+8------->1
n=3Dy+21--------->2
from 1 & 2 D(x-3y)=13
here 13 is prime number so it has factors 1 and 13 only
x-3y must be 1
let x=4 and y=1
then n=60
so 2n is divided that is 120 by 3D that is by 39 we get
the remainder as 3
| Is This Answer Correct ? | 107 Yes | 15 No |
Answer / ali salman
let n
n=Dx+8------->1
n=3Dy+21--------->2
from 1 & 2 D(x-3y)=13
here 13 is prime number so it has factors 1 and 13 only
x-3y must be 1
let x=4 and y=1
then n=60
so 2n is divided that is 120 by 3D that is by 39 we get
the remainder as 3
| Is This Answer Correct ? | 24 Yes | 3 No |
Answer / sourabh
let's number is n
so n=Dx+8------->1
n=3Dy+21--------->2
from 1 & 2 D(x-3y)=13
here 13 is prime number so it has factors 1 and 13 only
x-3y must be 1
let x=4 and y=1 BUT THESE NUMBER DONT SATISFY EQ 1 AND 2 IE
IF WE PUT X=4 IN 1 WE GET N=50 AND IF WE PUT Y = 1 IN 2 WE
GET N=60
SO WE LET X=7 AND Y = 2
then n=99
so 2n is divided that is 198 by 3D that is by 39 we get
the remainder as 3
| Is This Answer Correct ? | 13 Yes | 13 No |
Answer / avinash kulkarni
number be n
i.e divided by D i.e= n/D=8;
divided by 3D is n/3D=21;
question is n/3d=21 i.e 21/3D
so, 21/3*1/D
7*1/D=7/D
there is not at all possible to divide 7.. if so, we will get an ans in decimals
so, ANS IS....
Cannot be determined
| Is This Answer Correct ? | 1 Yes | 10 No |
Answer / pachi
let the number be X
then X/3D=21
If X/3D=21 then 2X/3D=?
2*X*21*3D/X*3D==42
| Is This Answer Correct ? | 1 Yes | 14 No |
if x=y=2z and xyz =256 then x=
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