Answer / sandip pal

#include<stdio.h>
#include<conio.h>
int ncr(int,int);
int fact(int);
void main()
{
int i,j;
clrscr();
for(i=0;i<=5;i++)
{
printf("\n\n");
for(j=0;j<=5-i;j++)
printf(" ");
for(j=0;j<=i;j++)
printf(" %2d ",ncr(i,j));
}
getch();
}
int ncr(int n,int r)
{
int f;
f=fact(n)/(fact(n-r)*fact(r));
return f;
}
int fact(int n)
{
if(n==0)
return 1;
else
n=n*fact(n-1);
return n;
}

Answer / ch.mahathi

could anyone please assist me in getting the output in the following way?

For example, if you have entered a pin number like 532211 as the input to the program , then the output should be like this



(5)+(5+3)+(5+3+2)+(5+3+2+1)+(5+3+2+2+1)+(5+3+2+2+1+1)

Answer / tknowledge05

The above guest is me .. ookk....
by the time i solved and executing i was logged out and when i posted the answer it considered guest.......

Answer / guest

#include<conio.h>
#include<stdio.h>
void main()
{
int a[10],b[10];
int c=1,n=5;
a[0]=0;a[1]=1;a[2]=0;
b[0]=0;
printf("Enter no. of rows to print ");
scanf("%d",&n);
for(int i=0;i<n;i++)
{
for(int j=n-2;j<0;j++)
printf(" ");
c++;
for(int k=0;k<c;k++)
{
b[k+1]=a[k]+a[k+1];
}
b[c]=0;
for(int k=1;k<=i+1;k++)
{
printf("%d ",a[k]);
}
printf("\n");
for(int k=0;k<i+3;k++)
a[k]=b[k];
}
getch();
}

Explain bit masking in c?

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Concat two string with most overlapped substring has to remove  "abcd"+ "cdef" = "abcdef

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Write a main() program that calls this function at least 10 times. Try implementing this function in two different ways. First, use an external variable to store the count. Second, use a local variable. Which is more appropriate?

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How can you read a directory in a C program?

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what will happen if you free a pointer twice after allocating memory dynamically ?

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n=7623 { temp=n/10; result=temp*10+ result; n=n/10 }

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in a town the percentage of men is 52 the percentage of total literacy is 48 if total percentage of literate men is 35 of the total population write a program to find the total no of the literate men and women if the population of the town is 80000

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You have given 2 array. You need to find whether they will create the same BST or not. For example: Array1:10 5 20 15 30 Array2:10 20 15 30 5 Result: True Array1:10 5 20 15 30 Array2:10 15 20 30 5 Result: False One Approach is Pretty Clear by creating BST O(nlogn) then checking two tree for identical O(N) overall O(nlogn) ..we need there exist O(N) Time & O(1) Space also without extra space .Algorithm ?? DevoCoder guest Posted 3 months ago # #define true 1 #define false 0 int check(int a1[],int a2[],int n1,int n2) { int i; //n1 size of array a1[] and n2 size of a2[] if(n1!=n2) return false; //n1 and n2 must be same for(i=0;i<n1-1;i++) { if( !( (a1[i]>a1[i+1]) && (a2[i]>a2[i+1]) ) ) return false; } return true;//assumed that each array doesn't contain duplicate elements in themshelves }

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how to print "hai" in c?

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