Answer / sneha

*A user thread is normally created by a threading library and scheduling is managed by the threading library itself (Which runs in user mode). All user threads belong to process that created them. The advantage of user threads is that they are portable.
*A kernel thread, sometimes called a LWP (Lightweight Process) is created and scheduled by the kernel. Kernel threads are often more expensive to create than user threads and the system calls to directly create kernel threads are very platform specific.
*The major difference can be seen when using multiprocessor systems, user threads completely managed by the threading library can't be ran in parallel on the different CPUs, although this means they will run fine on uniprocessor systems. Since kernel threads use the kernel scheduler, different kernel threads can run on different CPUs.
Many systems implement threading differently,
*A many-to-one threading model maps many user processes directly to one kernel thread, the kernel thread can be thought of as the main process.
*A one-to-one threading model maps each user thread directly to one kernel thread, this model allows parallel processing on the multiprocessor systems. Each kernel thread can be thought of as a VP (Virtual Process) which is managed by the scheduler.

Write a program of advanced Fibonacci series.

0 Answers   Aspiring Minds,

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which of the following statements is incorrect a.typedef struct new{ int n1; char n2; } DATA; b.typedef struct { int n3; char *n4; }ICE; c.typedef union { int n5; float n6; } UDT; d.#typedef union { int n7; float n8; } TUDAT;

5 Answers   Assurgent, TCS,

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1 Answers   Wipro,

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0 Answers   Vertex,

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3 Answers   TCS,

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0 Answers  

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You have an int array with n elements and a structure with three int members. ie struct No { unsigned int no1; unsigned int no2; unsigned int no3; }; Point1.Lets say 1 byte in the array element is represented like this - 1st 3 bits from LSB is one number, next 2 bits are 2nd no and last 3 bits are 3rd no. Now write a function, struct No* ExtractNos(unsigned int *, int count) which extracts each byte from array and converts LSByte in the order mentioned in point1.and save it the structure no1, no2, no3. in the function struct No* ExtractNos(unsigned int *, int count), first parameter points to the base address of array and second parameter says the no of elements in the array. For example: if your array LSB is Hex F7 then result no1 = 7, no2 = 2, no3 = 7. In the same way convert all the elements from the array and save the result in array of structure.

2 Answers   Qualcomm,

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0 Answers   MNC,

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2 Answers   Bosch, Wipro,

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cin.ignore(80, _ _);This statement a) ignores all input b) ignores the first 80 characters in the input c) ignores all input till end-of-line d) iteration

0 Answers  

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Find the highest of three numbers and print them using ascending orders?

1 Answers  

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i = 25;switch (i) {case 25: printf("The value is 25 ");case 30: printf("The value is 30 "); When the above statements are executed the output will be : a) The value is 25 b) The value is 30 c) The value is 25 The value is 30 d) none

0 Answers  

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