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struct abc
{
unsigned int a;
char b;
float r;
};
struct xyz
{
int u;
struct abc tt;
}ww;
ww = (struct xyz*)malloc(sizeof(struct xyz));
will the memory be allocated for the inner structure also?
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Answer / sadanand
Yes. when sizeof(xyz) is done. it will compute size of
struct abc + size of int
| Is This Answer Correct ? | 4 Yes | 1 No |
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I need help with the following lab. Can anyone explain it to me on how to approach this problem. Coding would be great too !!! No busy waiting allowed. Remember that Java monitors are 'signal and continue'. The input data is called the database (DB). In this problem, it consists of a single variable initialized in the main thread, to contain the current time of day in HH:MM:SS:mmm format (mmm is milliseconds) truncated to 3 digits. Threads follow these rules: 1. Readers may all attempt to read at the same time, but NOT if a writer is writing (i.e.; the writer is in the monitor. 2. Writing is exclusive (only 1 writer at a time, no readers while writing). 3. Options: (to be specified by instructor) a. Readers have absolute priority over writers. b. Writers have absolute priority over readers c. When a reader arrives and a writer is waiting, the reader is suspended behind the writer instead of being admitted immediately. Thus, a writer waits for readers that were running when it arrived, but does not to wait for new readers. You may program this in C++ or Java. There are 4 controlling input values: 1. r – number of readers 2. w – number of writers 3. R – delay for a reader to restart 4. W – delay for a writer to restart Create the following program consisting of 1 main process (your main program) with n threads: 1. The main thread: a. Creates the 'n' threads needed. Of these, r of them are readers and w of them are writers. Starts all readers and writers. b. Waits for all 'n' threads to complete. You may use any method to detect when they are all complete. c. Prints out the resulting outputs from the threads. 2. Threads: a. When a thread starts to run, it immediately tries to enter the monitor. b. A reader thread reads the DB, outputs the exact message below, then exits: >>> DB value read =: HH:MM:SS:mmm by reader number: rr where the underlined text is replaced with actual data. c. A writer thread updates the DB with a new value (from the system time), outputs the exact message below, then exits: *** DB value set to: HH:MM:SS:mmm by writer number: ww where the underlined text is replaced with actual data. d. Each thread accesses the data a total of 10 times, exiting, then re-entering the monitor after each access. Hints: 1. File access *might* not be thread-safe, so you should be prepared to handle this. Read the documentation for the language you are using. 2. Suggested values for delays are: a. If looping, R >=1,000,000 and W>=100,000 b. If using “sleep”, then R=100 ms, W=50 ms. Additional: • Thread output is to ONE file used by ALL threads (so you need to synchronize access to it). • Readers must provide sufficient delay that results are useful (delay by R before re-trying). R is another input value. • Writers must also delay. Delay by W, updating the DB each time. W is an input. • Test your program with AT LEAST TWO different sets of values for r and w (#s of readers and writers) plus this set: r = 4, w=2. Basic operation of a thread: attempt to enter the monitor. If unsuccessful, you get put on a queue. When you get in, read or write the data (depending on type of thread), exit the monitor, wait the required delay amount, then try again. Repeat 10 times.
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Hello friends !!! I’am Abhinav Ranjan Sinha College- L.K.C.T(Indore) I just want to express my personnal experience of getting placed at Consagous Technologies,to all freshers who are in search of the job. On 25th of Feb 2011 there was a campus drive of Consagous Technologies in our college.That was the second time any software company is coming to our college for batch, I was very excited. Firstly, they started with a seminar, a small introduction about the company.Then as the first round of the placement process, they conducted GD, in every group there was 20 students, and in the GD they just given the topics on the current affairs ,like- Global warming, Science is a curse or boon, girls are superior than boys?, etc. Then after half an hour the result of GD was announced , and fortunetly I was selected among the 150 other students. Then there was a written round, that was fully Technical , the question paper consists of total 50 questions out which 45 are optional and the rest of the 5 questions are not optional. Some of them which I remember are- 1.when we pass an argument to a function , then how it is being interpreted? Ans- Address of the first element of an array. 2.how the size of structure can be determined? 3.Complexity of binary search algorithm? Ans-0(logn) 4.what does the symbol << do in c++? 5.what does (.) dot operator do? 6.what is RTTI? 7.What is containership? And many more questions related to data structure on complexity, C program output, etc Then the result was declared on the next day, total 45 students are short leasted out of 150(approx) and the further rounds of Technical and HR are after two days. Then on 28th of Feb 2011 we are called for the next rounds, and that was the toughest time ever as my turn came almost at last , firstly my name was announced for the Technical round, there when I entered there are 3 persons inside the room who are taking the interview, as I entered they asked me to reduce the speed of the fan, I went to the switch board but the regulator was not working , then they told me to switch it off. Then , they offerd me to have a seat, there they asked me about- 1. what is your area of interest? 2. what is recursion? 3. write a program of factorial using recursion. 4. differentiate between My sql and Sql server. 5. they asked me questions related to my minor project. 6. what does get and post method do? 7. what is structure? 8. what is union? Out of which I have given answers of the many of them. Then I was called for the PI (personnmal interview) , I was very tired as it was 6:30 and I was waiting for my turn from 11’o clock onwards. But as I was very much exited , I just prayed to God and entered in the room, As I entered I saw two persons there inside the room I wished both of them, and they offerd me the chair, I replied with thank you sir thank you mam. Then the first question which I was asked there is- 1.Tell me something about yourself? Then, 2.they asked me of my strengths. 3.then suddenly they started asking aptitude questions, and the main thing is that they are not repeating the questions, you have to listen it very carefully. And the questions are like— Que- a man moves 50 km away from his house in the north direction, then he turns left and moves 50 km , and then again he turns left and moves 50 km, then at which place he is from his house and at what distance? Que- the ratio of the age of the two friends are in the ratio 6:5 then there ratio becomes 8:7 , so how many years they will it takes to gain this ratio? 4.where do you see yourself after 5 years? 5.tell me your 5 such skills which you can give to our organization. 6.what do you know about our company? They both are very calm and are of very good nature, and they are very supportive which helped me a lott . And just after half an hour the results had been declared and fortunetly with God’s Grace I got selected, that was the one of the very most imported and cherishable moment of my life. All The Best to all my dear friends , and I wish you for your bright future. And , at last but not the least, I would like to thanks to Consagous Technologies to give me such a big opportunity to prove myself in my life, thank you so much.
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C 
