Write a program using bitwise operators to invert even bits of
a given number.
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#include<stdio.h>
int main()
{
int n,n2;
printf("enter the no. < 15 "); // here i am considering the case of 4 bits. (1111) binary = (15) decimal
scanf("%d",&n);
n2=n^10;
/*
10 = 1010 in binary form, to invert its even bits , we will
use bit wise XOR (^) operator
1010 has 1 at its even places, so it will invert the even bits of n.
if there is any further problem mail me at
buntyhariom@gmail.com
www.campusmaniac.com
*/
printf("\n%d",n2);
return 0;
}
| Is This Answer Correct ? | 10 Yes | 2 No |
Answer / ayaskanta
Use Xor operation. Xor ing with 1 coverts a 0 to 1 and a 1
to zero...
| Is This Answer Correct ? | 3 Yes | 3 No |
what is the c source code for the below output? 5555555555 4444 4444 333 333 22 22 1 1 22 22 333 333 4444 4444 5555555555
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