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70% of people reads morning news paper
40% of people reads evening newspaper
20% of people reads neither morning nor evening newspapers
1 prob who reads at least one newspaper
2 prob who reads both newspaper
3 prob who reads only one newspaper
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Answer / smruti tandra
20% ppl nither reads morn nor reads evn
i.e,80% ppl reads nes ppr
1 prob=80/100=0.8
70-40=30
30% ppl reads both
2 prob=30/100=0.3
70-30=40%of ppl reads only morn news ppr
40-30=10%0f ppl reads only even news ppr
40+10=50%of ppl reads only 1 news ppr
3 prob=50/100=0.5
| Is This Answer Correct ? | 27 Yes | 3 No |
Answer / pinks
1=0.8
2=0.3
3=0.5
i have just tried i want its true answers
| Is This Answer Correct ? | 20 Yes | 6 No |
Answer / sandeep gupta
1. At least one paper = Total people - Non-reader
= 100-20=80.
2. P(M)=70,P(E)=40,MuE= 80 (from question#1),
Hence, MuE= P(M)+ P(E)-Both Newspaper reader(Common)
80=70+40-Both newspaper reader(Common)
Both newspaper reader(Common)=110-80=30.
3.who reads only Morning=70-30 (from question#2)=40.
who reads only Morning=40-30 (from question#2)=10.
Total of who read only one paper (M or E)= 40+10=50
| Is This Answer Correct ? | 6 Yes | 0 No |
Answer / yogesh
20% people read neither moring nor evening paper
80% people read alteast one newspaper
30% people read both newspaper
10% people read only evening newspaper
70% people read only morning newspaper
| Is This Answer Correct ? | 7 Yes | 8 No |
Answer / saravanan
% wont exceeds 100%. so no answer for this question
| Is This Answer Correct ? | 2 Yes | 6 No |
Answer / priya
1 prob ans is 30%
2 prob ans is 80%
3 prob ans is 50%
| Is This Answer Correct ? | 1 Yes | 5 No |
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