Answer / riteshvk007

#include<stdio.h>
#include<conio.h>
void main()
{
int bs,da,hra;
clrscr();
printf("\n enter the basic salary of employee");
scanf("%d",&bs);
if (bs>10000)
{
printf("\n da : %d",da=bs*15/100);
printf("\n hra : %d",hra=bs*13/100);
printf("\n net salary: %d",da+hra);
}
else
{
printf("\n da : %d",da=bs*20/100);
printf("\n hra : %d",hra=bs*18/100);
printf("\n net salary: %d",da+hra);
}
getch();
}

plese cheackout mistakes i can't run successfully this program

Answer / rama krishna sidhartha

#include<stdio.h>
#include<conio.h>
void main()
{
long int bs,da,hra;
clrscr();
printf("\n enter the basic salary of employee=");
scanf("%f",&bs);
if (bs<10000)
{
printf("\n da : %f",da=(bs*15)/100);
printf("\n hra : %f",hra=(bs*13)/100);
printf("\n net salary: %f",da+hra);
}
else
{
printf("\n da : %f",da=(bs*20)/100);
printf("\n hra : %f",hra=(bs*18)/100);
printf("\n net salary: %f",da+hra);
}
getch();
}

Answer / swapnil

#include<stdio.h>
#include<conio.h>
void main()
{
float bs,da,hra;
clrscr();
printf("\n enter the basic salary of employee=");
scanf("%f",&bs);
if (bs<10000)
{
printf("\n da : %f",da=(bs*15)/100);
printf("\n hra : %f",hra=(bs*13)/100);
printf("\n net salary: %f",da+hra);
}
else
{
printf("\n da : %f",da=(bs*20)/100);
printf("\n hra : %f",hra=(bs*18)/100);
printf("\n net salary: %f",da+hra);
}
getch();
}

Answer / parmeshwar

#include<stdio.h>
#include<conio.h>
void main()
{
long int bs,da,hra;
clrscr();
printf("\n enter the basic salary of employee=");
scanf("%f",&bs);
if (bs<10000)
{
printf("\n da : %f",da=(bs*15)/100);
printf("\n hra : %f",hra=(bs*13)/100);
printf("\n net salary: %f",da+hra);
}
else
{
printf("\n da : %f",da=(bs*20)/100);
printf("\n hra : %f",hra=(bs*18)/100);
printf("\n net salary: %f",da+hra);
}
getch();
}

Answer / swapnil

#include<stdio.h>
#include<conio.h>
void main()
{
int bs,da,hra;
clrscr();
printf("\n enter the basic salary of employee");
scanf("%d",&bs);
if (bs<10000)
{
printf("\n da : %d",da=bs*15/100);
printf("\n hra : %d",hra=bs*13/100);
printf("\n net salary: %d",da+hra);
}
else
{
printf("\n da : %d",da=bs*20/100);
printf("\n hra : %d",hra=bs*18/100);
printf("\n net salary: %d",da+hra);
}
getch();
}

Answer / swapnilkumar

3 no solution is correct please run this code u will get result

18)struct base {int a,b; base(); int virtual function1(); } struct derv1:base{ int b,c,d; derv1() int virtual function1(); } struct derv2 : base {int a,e; } base::base() { a=2;b=3; } derv1::derv1(){ b=5; c=10;d=11;} base::function1() {return(100); } derv1::function1() { return(200); } main() base ba; derv1 d1,d2; printf("%d %d",d1.a,d1.b) o/p is a)a=2;b=3; b)a=3; b=2; c)a=5; b=10; d)none 19) for the above program answer the following q's main() base da; derv1 d1; derv2 d2; printf("%d %d %d",da.function1(),d1.function1(),d2.function1 ()); o/p is a)100,200,200; b)200,100,200; c)200,200,100; d)none 20)struct { int x; int y; }abc; you can not access x by the following 1)abc-->x; 2)abc[0]-->x; abc.x; (abc)-->x; a)1,2,3 b)2&3 c)1&2 d)1,3,4

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