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i want to asked a question about c program the question is:
create a c program that displays all prime numbers less than
500? using looping statement
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Answer / vadivelt
Hi.
Have a look on the code i hav written below.
Just give max no(in this question 500) as a input, u ll get
the prime nos in this range.
#include<stdio.h>
#include<conio.h>
main()
{
int n, j, k, flag = 0;
printf("ENTER THE NO\n");
scanf("%d", &n);
printf("\nPRIME NOS IN THIS RANGE\n");
for(j = 1; j<= n; j++)
{
for(k = j; k>=1; k--)
{
if(j%k == 0)
flag++;
}
if(flag == 2)
{
printf("%d ", j);
}
flag = 0;
}
getch();
}
| Is This Answer Correct ? | 3 Yes | 0 No |
Answer / vadivelt
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / ashwin kumar
I hope this is right code for you
1st it promt for max number then enter 500 then you will
get result.
#include<stdio.h>
#include<conio.h>
int main()
{
int value,j,i,value2,flag=0,count=0;
clrscr();
printf("enter limit up to which prime numbers to be
printed : ");
scanf("%d",&value2);
printf("\n\n\nlist of prime numbers are:\n\n");
for(j=1;j<=value2;j++)
{
flag=0;
value=j;
for(i=2;i<value;i++)
{
if(value%i==0)
{
flag=flag+1;
goto l1;
}
}
l1:
if(!(flag==1||value==2))
{
printf("%-10d",value);
count+=1;
}
}
printf("\n\ntotal number of prime numbers between 1 and %d
are : %d",value2,count);
getch();
return 0;
}
if their is any changes required or any suggestions mail
me at molugu.ashwin@gmail.com
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / ashwin kumar
its just to find weather given number is prime or not
#include<stdio.h>
#include<conio.h>
int main()
{
int value,i,flag=0;
clrscr();
printf("enter value to check for prime number : ");
scanf("%d",&value);
for(i=2;i<value;i++)
{
if(value%i==0)
{
flag=flag+1;
break;
}
}
if(flag==1||value==2)
printf(" %d is not a prime number",value);
else
printf(" %d is a prime number",value);
getch();
return 0;
}
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / vishnu nayak
int main()
{
unsigned int i,k;
unsigned int temp;
int count =0;
printf("enter the number \n");
scanf("%u",&i);
printf("\n");
for(temp =2;temp<i;temp++)
{
count =0;
for(k =2;k<=i;k++)
{
if((temp % k) == 0)
count++;
}
if(count <=1 )
printf("%u \n",temp);
}
getch();
}
| Is This Answer Correct ? | 1 Yes | 1 No |
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