Answer / sreejesh1987

//This code displays prime factors only

#include<stdio.h>
#include<conio.h>
void main()
{
int i,j,n,x,flag=0,d,count=0;
clrscr();
printf("\tPRIME CHECK\n");
printf("Enter a no:");
scanf("%d",&n);

for(j=2;j<n,n%j!=0;j++)
if(n-1==j)
{
printf("\n\t%d is a prime",n);

flag=1;
}

if(!flag)
{
printf("\nNumber %d is not a prime",n);
printf("\nIts factors are:\n\t");

x=2;
while(n!=1)
{

while(n%x==0)
{
n=n/x;
printf("%d ",x);
count++;
}
x++;
}
printf("\nNumber of factors:%d",count);
}
getch();
}

Answer / kracekumar

to check a number is prime or not ,it is enough to check till square root(floor) of the number is divisible or not.
#include<stdio.h>
#include<math.h>
/*
WHILE COMPILING IN LINUX USE gcc -lm -o factor factor.c and execute ./factor
*/
void isprime(int factor)
{
/*This function will check the given factor of the no is prime or not if so it will print the number factor as (prime)*/
int inner_loop,sqrt_of_factor;
sqrt_of_factor=(int)sqrt((double)factor);//in sqrt function will take float or double argument
if(factor==2)
printf("(prime)");
else
{/*To find out the no is prime or not you need to find out square root and from 2 to square root of the no if the no is not divisble by the no it is called as prime no*/
for(inner_loop=2;inner_loop<=sqrt_of_factor;++inner_loop)
{
if(factor%inner_loop==0)//if it divisble it exit the looop
break;
}
if(inner_loop>sqrt_of_factor)
/*best part is this checking ,if the no(factor) is prime it should be exited the loop with the loop variable value greater than condition varibale value */
printf("(prime)");
}
}
void factor(int no)
{
int start,no_by_2=no/2;
/*no_by_2 is used because factor of a no will be in the range 1 to half the number */
printf("\n factors of %d are %d",no,1);
for(start=2;start<no_by_2;++start)
{
if(no%start==0)
{
printf("\t %d",start);
isprime(start);//checking the factor is prime or not
}
}
printf("\t %d",no);
isprime(no);
}
int main()
{
system("clear");//work only in LINUX
int no;
printf("\n enter the integer no for which factor is to be found:");
scanf("%d",&no);
factor(no);
printf("\n \n=================================================\n");
return 0;
}

What is wrong with this initialization?

0 Answers  

---

Explain what are the different file extensions involved when programming in c?

0 Answers  

---

write a C program : To find out the number of identical words in two files . the file name should be taken as command line argument .

1 Answers   Subex,

---

#include <stdio.h> int main ( int argc, char* argv [ ] ) { int value1 = 10; int value2 = 5; printf ( "\n The sum is :%d", value1 | value2 ); } This is the answer asked by some one to add two numbers with out using arithmetic operator?Yes this answer is write it given out put as 15.But how????? what is need of following line? int main ( int argc, char* argv [ ] ) how it work?what is the meaning for this line? please explain me.Advance thanks

9 Answers   Excel,

---

Write a program to produce the following output: 1 2 3 4 5 6 7 8 9 10

1 Answers   CMS,

---

the output will be #include<stdio.h> int main () { int i; i = 9/2; printf("%i",i); return 0; }

4 Answers   CMC, TCS,

---

Explain #pragma statements.

0 Answers  

---

Write a C++ program to give the number of days in each month according to what the user entered. example: the user enters June the program must count number of days from January up to June

0 Answers  

---

why java is called as a purely oops language.

3 Answers   TVS,

---

Why is this loop always executing once?

0 Answers  

---

What is #include stdlib h?

0 Answers  

---

What are different types of operators?

0 Answers  

---