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Explain function pointer with exapmles.

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Explain function pointer with exapmles...

Answer / kiran

please reffer below information..........

Programs as Data: Function Pointers

A function pointer is a variable that stores the address of
a function that can later be called through that function
pointer. This is useful because functions encapsulate
behavior. For instance, every time you need a particular
behavior such as drawing a line, instead of writing out a
bunch of code, all you need to do is call the function. But
sometimes you would like to choose different behaviors at
different times in essentially the same piece of code. Read
on for concrete examples.

Example Uses of Function Pointers


Functions as Arguments to Other Functions

If you were to write a sort routine
<http://www.cprogramming.com/tutorial/computersciencetheory/sortcomp.html>
, you might want to allow the function's caller to choose
the order in which the data is sorted; some programmers
might need to sort the data in ascending order, others might
prefer descending order while still others may want
something similar to but not quite like one of those
choices. One way to let your user specify what to do is to
provide a flag as an argument to the function, but this is
inflexible; the sort function allows only a fixed set of
comparison types (e.g., ascending and descending).

A much nicer way of allowing the user to choose how to sort
the data is simply to let the user pass in a function to the
sort function. This function might take two pieces of data
and perform a comparison on them. We'll look at the syntax
for this in a bit.

Callback Functions

Another use for function pointers is setting up "listener"
or "callback" functions that are invoked when a particular
event happens. The function is called, and this notifies
your code that something of interest has taken place.

Why would you ever write code with callback functions? You
often see it when writing code using someone's library. One
example is when you're writing code for a a graphical user
interface (GUI). Most of the time, the user will interact
with a loop that allows the mouse pointer to move and that
redraws the interface. Sometimes, however, the user will
click on a button or enter text into a field. These
operations are "events" that may require a response that
your program needs to handle. How can your code know what's
happening? Using Callback functions! The user's click should
cause the interface to call a function that you wrote to
handle the event.

To get a sense for when you might do this, consider what
might happen if you were using a GUI library that had a
"create_button" function. It might take the location where a
button should appear on the screen, the text of the button,
and a function to call when the button is clicked. Assuming
for the moment that C (and C++) had a generic "function
pointer" type called function, this might look like this:
void create_button( int x, int y, const char *text, function
callback_func );
Whenever the button is clicked, callback_func will be
invoked. Exactly what callback_func does depends on the
button; this is why allowing the create_button function to
take a function pointer is useful.

Function Pointer Syntax

The syntax for declaring a function pointer might seem messy
at first, but in most cases it's really quite
straight-forward once you understand what's going on. Let's
look at a simple example:
void (*foo)(int);
In this example, foo is a pointer to a function taking one
argument, an integer, and that returns void. It's as if
you're declaring a function called "*foo", which takes an
int and returns void; now, if *foo is a function, then foo
must be a pointer to a function. (Similarly, a declaration
like int *x can be read as *x is an int, so x must be a
pointer to an int.)

The key to writing the declaration for a function pointer is
that you're just writing out the declaration of a function
but with (*func_name) where you'd normally just put func_name.



Reading Function Pointer Declarations

Sometimes people get confused when more stars are thrown in:
void *(*foo)(int *);
Here, the key is to read inside-out; notice that the
innermost element of the expression is *foo, and that
otherwise it looks like a normal function declaration. *foo
should refer to a function that returns a void * and takes
an int *. Consequently, foo is a pointer to just such a
function.

Initializing Function Pointers

To initialize a function pointer, you must give it the
address of a function in your program. The syntax is like
any other variable:
#include <stdio.h>
void my_int_func(int x)
{
printf( "%d\n", x );
}

int main()
{
void (*foo)(int);
/* the ampersand is actually optional */
foo = &my_int_func;

return 0;
}
(Note: all examples are written to be compatible with both C
and C++.)

Using a Function Pointer

To call the function pointed to by a function pointer, you
treat the function pointer as though it were the name of the
function you wish to call. The act of calling it performs
the dereference; there's no need to do it yourself:
#include <stdio.h>
void my_int_func(int x)
{
printf( "%d\n", x );
}


int main()
{
void (*foo)(int);
foo = &my_int_func;

/* call my_int_func (note that you do not need to write
(*foo)(2) ) */
foo( 2 );
/* but if you want to, you may */
(*foo)( 2 );

return 0;
}
Note that function pointer syntax is flexible; it can either
look like most other uses of pointers, with & and *, or you
may omit that part of syntax. This is similar to how arrays
are treated, where a bare array decays to a pointer, but you
may also prefix the array with & to request its address.

Function Pointers in the Wild

Let's go back to the sorting example where I suggested using
a function pointer to write a generic sorting routine where
the exact order could be specified by the programmer calling
the sorting function. It turns out that the C function qsort
does just that.

From the Linux man pages, we have the following declaration
for qsort (from stdlib.h):
void qsort(void *base, size_t nmemb, size_t size,
int(*compar)(const void *, const void *));
Note the use of void*s to allow qsort to operate on any kind
of data (in C++, you'd normally use templates
<http://www.cprogramming.com/tutorial/templates.html> for
this task, but C++ also allows the use of void* pointers)
because void* pointers can point to anything. Because we
don't know the size of the individual elements in a void*
array, we must give qsort the number of elements, nmemb, of
the array to be sorted, base, in addition to the standard
requirement of giving the length, size, of the input.

But what we're really interested in is the compar argument
to qsort: it's a function pointer that takes two void *s and
returns an int. This allows anyone to specify how to sort
the elements of the array base without having to write a
specialized sorting algorithm. Note, also, that compar
returns an int; the function pointed to should return -1 if
the first argument is less than the second, 0 if they are
equal, or 1 if the second is less than the first.

For instance, to sort an array of numbers in ascending
order, we could write code like this:
#include <stdlib.h>

int int_sorter( const void *first_arg, const void *second_arg )
{
int first = *(int*)first_arg;
int second = *(int*)second_arg;
if ( first < second )
{
return -1;
}
else if ( first == second )
{
return 0;
}
else
{
return 1;
}
}

int main()
{
int array[10];
int i;
/* fill array */
for ( i = 0; i < 10; ++i )
{
array[ i ] = 10 - i;
}
qsort( array, 10 , sizeof( int ), int_sorter );
for ( i = 0; i < 10; ++i )
{
printf ( "%d\n" ,array[ i ] );
}

}

Using Polymorphism and Virtual Functions Instead of Function
Pointers (C++)

You can often avoid the need for explicit function pointers
by using virtual functions. For instance, you could write a
sorting routine that takes a pointer to a class that
provides a virtual function called compare:
class Sorter
{
public:
virtual int compare (const void *first, const void *second);
};

// cpp_qsort, a qsort using C++ features like virtual functions
void cpp_qsort(void *base, size_t nmemb, size_t size, Sorter
*compar);
inside cpp_qsort, whenever a comparison is needed,
compar->compare should be called. For classes that override
this virtual function, the sort routine will get the new
behavior of that function. For instance:
class AscendSorter : public Sorter
{

virtual int compare (const void*, const void*)
{
int first = *(int*)first_arg;
int second = *(int*)second_arg;
if ( first < second )
{
return -1;
}
else if ( first == second )
{
return 0;
}
else
{
return 1;
}
}
};
and then you could pass in a pointer to an instance of the
AscendSorter to cpp_qsort to sort integers in ascending order.

But Are You Really Not Using Function Pointers?

Virtual functions are implemented behind the scenes using
function pointers, so you really are using function
pointers--it just happens that the compiler makes the work
easier for you. Using polymorphism can be an appropriate
strategy (for instance, it's used by Java), but it does lead
to the overhead of having to create an object rather than
simply pass in a function pointer.

Function Pointers Summary


Syntax


Declaring

Declare a function pointer as though you were declaring a
function, except with a name like *foo instead of just foo:
void (*foo)(int);

Initializing

You can get the address of a function simply by naming it:
void foo();
func_pointer = foo;
or by prefixing the name of the function with an ampersand:
void foo();
func_pointer = &foo;

Invoking

Invoke the function pointed to just as if you were calling a
function.
func_pointer( arg1, arg2 );
or you may optionally dereference the function pointer
before calling the function it points to:
(*func_pointer)( arg1, arg2 );

Benefits of Function Pointers


* Function pointers provide a way of passing around
instructions for how to do something
* You can write flexible functions and libraries that
allow the programmer to choose behavior by passing function
pointers as arguments
* This flexibility can also be achieved by using
classes with virtual functions

Is This Answer Correct ?    1 Yes 0 No

Explain function pointer with exapmles...

Answer / vishnu

int temp(char t, int k)
{
t = 'd';
k = 90;
return 1;

}

int main()
{

int (* fun)(char ch, int i);// function pointer
fun = temp;
}

Is This Answer Correct ?    0 Yes 0 No

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