What is the difference between: x=a+b+c+d; and
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Answer / tathagata
x=a+b+c+d will result in a missing value if any one of the
value in a,b,c or d is missing.
x=sum(a,b,c,d) will give the sum assuming the missing value
|Is This Answer Correct ?||21 Yes||0 No|
Answer / mohana priya.m
x=a+b+c+d;->The integer value gets stored in the value x.
x=sum(a,b,c,d);->the return value of the function sum
(a,b,c,d) gets stored in the value x.
|Is This Answer Correct ?||9 Yes||1 No|
Answer / mohana priya.m
x=a+b+c+d --------> This will add the values of a,b,c and d
and finally assign the resulted value into x.
x=sum(a+b+c+d) ---> This will call the library procedure
named sum() in-order to calculate the sum of a,b,c and d.
Both will results in same answer
|Is This Answer Correct ?||7 Yes||2 No|
Answer / inbee
X=a+b+c+d > it is inline case. The + operator is overloaded
such a way the right side object's value will be added with
the left one and goes on. As is is a inline call the
execution of this statement is faster.
X = sum(a+b+c+d) > here the compiler need a switch to the
location in the memory where this library procedure is
written. And once the whore procedure get execute the
execution control need to shift back to the line. So it is
time consuming task. Also the data type of 'x' depends on
the return type of the sum().
|Is This Answer Correct ?||3 Yes||0 No|
Answer / nikita
In x=a+b+c+d we get sum of four integer, but x=sum(a,b,c,d) not get sum of four integer.
|Is This Answer Correct ?||4 Yes||11 No|
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