Answer / richa

The term "operator new" is used incase when u are
overloading the global "new" operator.We can overload ne
operator just as any other operators i.e +,-,*,=etc.

The term "new operator" is used in case of dynamic
allocation of memory.When a variable is allocated memory
dynamically the new operator is used.
Eg:
int *p=new int;
//here p is pointer to integer.So in order to allocate
memory for it we have used the new operator.

What is the difference between function overloading and operator overloading?

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What is class definition in c++ ?

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Is nan a c++?

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1)#include <iostream.h> int main() { int *a, *savea, i; savea = a = (int *) malloc(4 * sizeof(int)); for (i=0; i<4; i++) *a++ = 10 * i; for (i=0; i<4; i++) { printf("%d\n", *savea); savea += sizeof(int); } return 0; } 2)#include <iostream.h> int main() { int *a, *savea, i; savea = a = (int *) malloc(4 * sizeof(int)); for (i=0; i<4; i++) *a++ = 10 * i; for (i=0; i<4; i++) { printf("%d\n", *savea); savea ++; } return 0; } The output of this two programs will be different why?

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Show the declaration for a static function pointer.

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What is this pointer in c++?

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How many keywords are used in c++?

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Explain register storage specifier.

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Why struct is used in c++?

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i want to know how to copy arrary without using any method or function. I have tried the below using System; class e4 { static void Main(string[] args) { int a,b; int[ ] m= new int[5]; int[ ] n= new int[5]; for(a=0;a<=4;a++) { Console.WriteLine("enter any value"); m[a]=Convert.ToInt32(Console.ReadLine()); m[a]=n[a]; } for(b=0;b<=4;b++) { Console.WriteLine(n[b]); } } } but it will give wrong result can anyone solve this problem

1 Answers   Reliance,

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What is boyce codd normal form in c++?

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Distinguish between a # include and #define.

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