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HAL Database Management Interview Questions
Questions Answers Views Company eMail

Define view, sequence and index in DBMS.

988

What are the properties of a primary key in DBMS?

999

What is write ahead logging in DBMS?

1139

Post New HAL Database Management Interview Questions




Un-Answered Questions

Do encrypted files contain password in some form?

2113


Can I purchase microsoft outlook by itself?

3


What is the latest version of ambari that is available in the market and what is the feature that they have added in it?

81


Explain the steps in writing a java program using jdbc?

1027


Can you give an example showing javascript hoisting?

910


What is the advantage of android?

1005


How many tags are provided in jstl?

1203


sir i m final year diploma(mech. engg)student, can i apply for psu,s as like sail, bhel,gail,dmrc.etc..if yes then give me detall about iton my e-mail id meatul90@rediffmail.com...thank you.........

2908


Hi Friends, I worked with 8.2 not with 9.2. Please help me in this prob. I created one script and recorded some think and save as Test 1 then I opened process--open the object repository manager. Switch to file->save->give some name->save as Objectrepo1.tsr file. (This is the global repository file.) Then I went to object repository->tools-> associate repository ->click + icon ->open the previously saved Objectrepo1.tsr file. This is the global repository Now I created one more script and save as Test 2. In this script I am calling script with the Help of "Call of existing action" and I executed but QTP is not able to execute B’cos it is QTP is not able to read the Object Repository of Test 1. Please let me know why? Once I made Script 1 as a shared Obj. Repository so it would not give any Problem. Right?

2006


Why is inheritance not desirable in swift?

885


How to debug a web application which is hosted on iis?

934


Which xml parser comes with weblogic server 6.1?

905


How can you create a Task Notifications Workflow in SharePoint?

884


I want to JCL sort for Non-COMP and COMP-3 fields SORT FIELDS=(1,5,A,6,11,A,12,11,A,19,1,A,20,1,A),FORMAT=BI,EQUALS Length of comp bytes is 11 bytes which start at 6byte and 12 byte considering 11 bytes in comp-3 is 6 bytes. Can anyone tell if the above sort work SORT FIELDS=(1,5,A,6,6,A,12,6,A,19,1,A,20,1,A),FORMAT=BI,EQUALS does not works OK

1989


Can a key be both primary and foreign?

1053