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Find out the distinct numbers that can be formed by 2, 3,
7, 6(don?t now exactly) that should be divided by 4?
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Answer Posted / lajapathy
last two numbers are any one of 32,36,72,76
first digit 4C1 second digit 4C1
so 4C1 X 4C1 X 4(four combinations of last two digits)
= 64
64 possible ways
| Is This Answer Correct ? | 7 Yes | 8 No |
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