a clock which gains uniformly was observed to be 5min
slow at 12 noon on monday. it was noticed 10 min fast at
6pm . on the next day .when did the watch show the correct
time (* PLEASE GIVE THE EXPLANATION*)
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Answer Posted / swetha
It is 5 minutes slow at 12 noon and is seen to be 10 minutes fast at 6 pm the next day.So the total minutes which the clock has gained is 15 minutes. The total number of hours to gain 15 minutes is 30 hours.So to gain 5 minutes ,we have to cross multiply
2×30/15=10 hours
Therefore add 10 hours to 12 noon .You get the answer as 10 pm on the same day.
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