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There are 80 coins, among them one coin weighs less compared
to other. You are given a physical balance to weigh. In how
many wieghings the odd coin can be found.
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Answer Posted / amit mugal
Lets divide 80 into 27, 27 and 26
CASE 1: weigh 27 and 27.
IF weighs different, then next it wsll take 3 more times to get to the faulty one. So total of 4. END
Else same weight then count is 1 and take the sample of 26 den
CASE 2: Divide 26 into 9,9 and 8
Weigh 9 and 9
IF weighs different, then next it will take 2 more times to get to the faulty one. So total= 2+2=4. END
Else if same weight, then count 2 and take the sample of 8.
CASE 3: Divide 8 into 3,3 and 2
Weigh 3 and 3
IF weighs different, then next it will take 1 more times to get to the faulty one. So total= 3+1=4. END
Else if same weight, then count 3 and take the sample of 2
Now one more time weighing is required to find out the faulty one between 2 samples. So 3+1=4. END
| Is This Answer Correct ? | 8 Yes | 2 No |
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