Trapezoidal footing length = 2m , B=1.7m D=0.5m and d-
0.15m. Can anybody help and calculate quantity of concrete
by explaining all formulas involved.
Answer Posted / sagar mistry
Here you have not given the column size.
So we assume column size 300mm X 300mm.
There is an Offset after the periphery of column & it is 75mm.
Rectangular Part
=L X B X H
=2 X 1.7 X 0.15
=0.51 cum
Trapezoidal Part
=(h/3)(A1 + A2 + SQRT ( A1 X A2 )
=((0.5-0.15)/3) ((2 X 1.7) + ((0.3+0.075)+(0.3+0.075)) + SQRT ((2 X 1.7) X ((0.3+0.075)+(0.3+0.075))
=0.12 ( 3.40 + 0.75 + 0.70 )
=0.57 cum
Total Concrete
=0.51 + 0.57
=1.08 cum
Is This Answer Correct ? | 8 Yes | 4 No |
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