If the load is 10Kw and power factor has to improve from 0.5
to 0.8,how can we select the capacitor rating
accordingly.Illustrate by showing formula?
Answer Posted / prasad damodar bhoir
kvar= kw (tan phi 1- tan phi 2)
cos phi 1= 0.5, phi 1= cos inverse 0.5= 60
cos phi 2= 0.8, phi 2= cos inverse 0.8= 36.86
kvar= 10 (tan60 - tan 36.86)= 10 (1.73-0.74)
kvar= 9.9
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